4.6 stroker kit?

[mustang dan]

does anyone make one?

This ad is not displayed to registered or logged-in members. Register your free account today and become a member on Mustang Forums!

[Acer2428]

Most of the major rotating assembly companies do.

Try CHP.

5.1L is the biggest right now I believe, but most are 5.0.

[David_K]

i have a friend with a 5.5L 99 cobra. used a 5.1 crank and bored it like .60 over or something. a set of pistons cost him 1200 dollas

[02StanGT]

These guys make one also.

[2000GT4.6]

ORIGINAL: David_K

i have a friend with a 5.5L 99 cobra. used a 5.1 crank and bored it like .60 over or something. a set of pistons cost him 1200 dollas

I think he is bull****ting you. If ya do a 60 over bore in a 4.6L block, it would probably glow if you dropped a light into the cyl.

Besides that cyl bore adds very little displacement. The largest kit i have seen with a stock block was a 5.1L.

[David_K]

ORIGINAL: 2000GT4.6

I think he is bull****ting you. If ya do a 60 over bore in a 4.6L block, it would probably glow if you dropped a light into the cyl.

Besides that cyl bore adds very little displacement. The largest kit i have seen with a stock block was a 5.1L.

nope its sleeved. ask code. i helped this guy put it together

[S9V9T]

ORIGINAL: David_K

nope its sleeved. ask code. i helped this guy put it together

David_K is talking about my motor. It is like a 5.3L or something. The bore on this motor is .154 over not .60 like David_K said... [sm=chairshot.gif]
the bore is 3.704 and the stroke is a 3.755... piston size is 3.695... rod length is 5.880. Put that all together and you will come up to a 324 cid. Here is the formula to come up with any cid:

Formula to Calculate the CID (Cubic Inch Displacement) of an engine:
R² × Pi × H × number of cylinders = CID (Cubic Inch Displacement)

In other words;
Radius of the bore squared × 3.14 × Stroke × number of cylinders = CID

For my engine with a 3.704" bore and a 3.755" stroke, the formula reads:
1.852² × 3.14 × 3.755" × 8 = 323.52772 CID = 324 CID

In other words;
1.852² (The radius of a 3.704" bore [1.852"] squared [multiplied by itself, or 1.852 × 1.852] × 3.14 (Pi = 3.14) × 3.755 (3.755" stroke) × 8 (The number of cylinders in this engine) = 323.52772 CID

This formula will work with any engine. For example, the Oldsmobile 350 V8, which has a bore of 4.057" and a stroke of 3.385" would be;
2.0285² × 3.14 × 3.385 x 8 = 349.88742333922 CID

A Ford 351 with a bore of 4" and a stroke of 3.5" would be;
2² × 3.14 × 3.5 × 8 = 351.68 CID

MAKE ANY SENSE?

[S9V9T]

By the way, you can get the stoker kit from me. But the kit cannot be used with an iron block, it has to be used with an aluminum block.

Kit includes:
Custom forged crank
Eagle rods
JE custom pistons
Cylinder sleeves

[S9V9T]

The bored out block (without sleeves):

[IMG]local://upfiles/21375/EA92D048449B410DA566F9BFFB63758E.jpg[/IMG]

[IMG]local://upfiles/21375/A9B06BAFA7714D4B97AB5A98444033FF.jpg[/IMG]

Piston that came out of the motor:

[IMG]local://upfiles/21375/0821B15114C04F95AB485052507392CD.jpg[/IMG]

[David_K]

ORIGINAL: David_K

i have a friend with a 5.5L 99 cobra. used a 5.1 crank and bored it like .60 over or something. a set of pistons cost him 1200 dollas

i meant lik .060 but i guess its alot bigger than that