I'm sure you have seen this topic many times and I've read lots, which has probably confused me. The car is a 65 289 and I fitted an accuspark electronic ignition (in distributor type) as per the instructions for the ballast resistor (attached) the car would fire but not run, points back on and it's fine. My problem is that there is a small unit to the right of the coil in the pictures attached which I assume is a ballast resistor, I cant think what else it could be. Can I just bypass this and wire up normally or is the wire from the ignition also a resistive wire? I wouldn't think there would be two types of resistance in he circuit. Coil is a Magfire 40Kv so I assume that can take 12v direct and not through the ballast.
Pics attached, I cant trace the grey wire and it doesn't correspond to the wiring diagrams I have but that should be fine with a full 12v.
As it's wired it should work. However, not if the ballast resistor on the side not attached to the coil doesn't have battery voltage on it with the ign key in run (will require a DVM to answer). If it is less than battery voltage that may be a problem since you may be current limiting the circuit current/voltage twice. The ballast resistor may also be bad (open most likely)
Any coil can withstand the direct battery voltage for some period -it will just over heat the coil leading to thermal failure. the coils that are designed for higher voltage just have better thermal aspects or lower failure failure consequences.
This forum is owned and operated by Internet Brands, Inc., a Delaware
corporation. It is not authorized or endorsed by the Ford Motor Company and is not affiliated with the Ford
Motor Company or its related companies in any way. FordŽ is a registered trademark of the Ford Motor