JFitz

Ford reps welcome to shed some light here.

Ok so, in another thread, I found this.

302 cubic inches on the 5.0 V8.

5 liters converts to 305.12 cubic inches. I'm not the best at math but my own ramblings on paper and google confirm this.

I'll chuck in another one - 4.6 liters converts to 280.71 cubic inches. I'm just kinda impressed by this figure because of the old 1 hp per cubic inch rule. Now we have a 280 (1 if we round?) that puts out 300 ft lbs of torque and 300 HP stock?
Ok ok, anyway. Where is Ford getting 302? Is this just one of those things because we like seeing "302" on the side for nostalgic reasons?

CMcNam

Sure is!

jpplaw

Bore x Bore x Stroke x 8 x .7854

3.63 x 3.63 x 3.65 x 8 x .7854 = 302.19

JFitz

AH! More math.

mapitts

We have a winner!

jpplaw

And will soon have 3.7 x 3.7 x 3.8 x 8 x .7854 = 326.86 !!

JFitz

I didn't know there was a formula for it.

CMcNam

I don't do maths good so if what jpplaw says is correct then go with that.

jpplaw

I memorized that formula a longgg time ago when I was building circle track engines

157dB

Engine Displacement Equation

The equation for any displacement in cubic inches is as follows:

π ÷ 4 (b2) (stroke) (number of cylinders)

That is pi divided by four, 0.7854, multiplied by the cylinder bore squared. Cylinder bore is the diameter (in inches) of each cylinder, times that number again. Multiply that by the stroke in inches of the crankshaft. In other words the distance each piston in the engine travels from bottom to top dead center. And finally multiply that by the number of cylinders that exist in that engine.