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so fellow S/S'er... I was bored tonight and figured some equations and broke down just exactly how to figure out how much more an N/A car suffers @ elevation as opposed to a FI car of the same caliber
alright, this is what I have concluded... if you guys find a flaw in my math, please, say something and correct it, like I said, I was bored and this is a one night sitting deal with windows notepad lol
figure out your TOTAL PSI @ sea level
(atmospheric pressure + boost pressure = TOTAL PSI)
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RULE #2
2,000ft of elevation = 1.1PSI drop from atmopsheric pressure (14.7)
(@ 6,000ft atmopsheric pressure = 11.4PSI)
#2
Figure out your CORRECTED PSI for your elevation and add it to your boost pressure
(2,000ft = -1.1PSI)
#3
Divide TOTAL sea level PSI into CORRECTED PSI
#4
your final product will be a percentage... you need to minus this percentage from 100% and this is your total percentage of BHP lost at given elevation through a forced induction application
#5
now that you have your percentage of power lost through your turbocharged application you need to find out what a N/A car would lose at the same BHP
so take your total PSI @ elevation and divide it into atmospheric pressure (considering there is no boost pressure)
#6
this percentage again, you need to minus from 100% and this is your total percentage of BHP lost at given elevation through a N/A application
now that you have percentages lost from both N/A and F/I application... now you have to figure out the difference in your given BHP between the two
this is how much of a help your forced induction is helping you at your elevation compared to other N/A cars
#7
TEST CAR
bone stock 2003 SVT cobra @ 6,000ft
stock PSI = 8PSI
#8
BREAKDOWN
14.7PSI + 8PSI = 22.7PSI
21.7 TOTAL PSI @ sea level for terminator
now factor in elevation
so...
14.7PSI - 3.3PSI = 11.4PSI
@ 6,000ft atmospheric pressure is 11.4PSI
now that we have corrected atmospheric pressure.... let's do the math
Quote:
8PSI + 11.4PSI = 19.4PSI
Quote:
19.4/22.7 = 85%
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100% - 85% = 15%
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15% of 390BHP = 59BHP
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390BHP - 59BHP = 331BHP
a terminator loses 14% of it's power @ 6,000ft... 15% of it's power is 59BHP, making a terminator into a 331BHP car @ 6,000ft
now let's equate for a naturally aspirated car for comparison to see just how much it's supercharger is helping it at elevation
math time...
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11.4/14.7 = 78%
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100% - 78% = 22%
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22% of 390BHP = 86BHP
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390bhp - 86bhp = 304BHP
seeing as a naturally aspirated engine with the same power output makes 304BHP and the terminator actually makes 331BHP @ 6,000ft we can conclude that 8PSI of boost pressure is helping the terminator make 27BHP @ 6,000ft... a small margin... but as boost pressure and elevation increases, so does this figure
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Last edited by Morbid Intentions; 10-20-2009 at 01:52 PM.
However, one advantage to below sea level....no need for an air to water intercooler
On a different note, interesting break down you have there morbid.
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Procharged 10PSI H.O. Intercooled
498whp/445wtq
For sale: plasma booster ignition
Quote:
Red Turbo Integra
That's the plan. The only thing that sucks is I have a dentist apointment in the morning. Hopefully all the numbing sh1t wears off quick so I don't look like a retard drooling on myself.
Howard well with NO2 you have air in a bottle... not quite the same
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Tngstn 06GT-5 spd -Vortech HO S/C-Tuned by Realspeed Auto
You can never have too much power, just not enough traction. 11.867 @ 119.35
turbo or nitrous seems to be the best way to go at high elevation... I'm still not bored enough to make the chart I was talking about making with different elevations/boost levels and losses for each.. sorry guys hehe I can give you people that find that sort of stuff fun the formula/math to do it though
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Just how much is your power adder helping you?
I can give you people that find that sort of stuff fun the formula/math to do it though 
