ZW99GT

Ok, so I know this is kind of a weird question, but I really dont know. I have a 3.75in crank, and the cylinders bored .030 over. Soooo, anybody know how to calculate the new displacement? Its a 5.1L stroker kit, so Im assuming 304-309? Thanks

kylebgt

I am pretty sure that the crank size does not matter when calculating displacement. I would say that you are around 306-307

ZW99GT

Crank size is the only thing that chages displacement with a stroker kit . The larger diameter crank=more up and down movement of the piston(a.k.a. longer stroke)
lol, I know that at least that much.

mustnglvr

Thats reasonably bigger then a 306. This is what I use for displacement figures .7854xbore2xstrokexnumber of cylinders. Are you sure thats your stroke?

ZW99GT

Im sure its a 3.75in crank. and its bored .030 over. Its supposed to be a 5.1L kit, so it shouldnt be much more than a 306-310. What is that .7854????

mustnglvr

Its just a simple formula

CoolAid

Bore X Bore X Stroke X .7854 X Number of Cylinders = Cubic Inchs. C.I. divided by 61.02 = Liters. I'd need your bore measurements to do the math.


EDIT: Example (I used to be a Chevy guy, cut me some slack): A 350 small block Chevy: 4.00x4.00x3.48x.7854x8 = 349.8 rounded to 350. 349.8 divided by 61.02 = 5.73 or 5.7 Liter. A non-exact way to get close to the cubes is just take Liters x 61.02 and it will give you a rough estimate, i.e.; 4.6L x 61.02 = 280.6 rounded to 281 c.i. (stock GT motor)