Got dynoed/tuned today.
#1
Got dynoed/tuned today.
Drove in and started with 385 RWHP and left with 424 RWHP in 102 degree heat. Definitely feels peppier and hopefully wont code anymore. Saw a set of Shelby mufflers (used) on the floor and had those put on to replace my flowmasters. Lot quieter in the car and the ^#%$^*%$#*^ drone is completely gone. Tuner said mufflers would only suck out 2-3 hp so preferred to eliminate the drone. Hope to have my first SCCA race Sunday and test it out. Edelbrock marketing appears to be full of crap. The Eforce ads say 5psi and 466 bhp out the box. I am pushing 8 psi after the intercooler and getting about 470 bhp after a day of tuning.
#3
congrats on the dyno tune.
when Edelbrock says 5 psi, that is not the peak psi, that is actually higher. so i agree with your statement that Edelbrock is pulling everyones leg with its low boost marketing scheme.
when Edelbrock says 5 psi, that is not the peak psi, that is actually higher. so i agree with your statement that Edelbrock is pulling everyones leg with its low boost marketing scheme.
#4
#5
#6
Looks like 15% drivetrain loss. So, 397 x 115% = 457 at the crank.
Does the drivetrain loss vary based on transmission on the Mustang? I had a supercharged 350Z a few years back and it was an automatic and the estimate was 20% loss for an auto and 15% loss for a manual.
Does the drivetrain loss vary based on transmission on the Mustang? I had a supercharged 350Z a few years back and it was an automatic and the estimate was 20% loss for an auto and 15% loss for a manual.
#9
The calculation is not 115% x rwhp. When you have 15% drivetrain loss, you multiply (1-.15) or .85 by the crank horsepower to get RWHP. So .85 x CrankHP = RWHP. Rewrite the equation to solve for CrankHP; CrankHP= RWHP/.85 So to solve for crank using RWHP, you divide by .85 (assuming 15% drivetrain loss).
424rwhp/.85 = 498.8 crank HP
424rwhp/.85 = 498.8 crank HP
#10