OneGearhead

simple forumula for figuring this out...

Pi(3.1416) x R x R x S x # of cylinders

R= radius of cylinder bore, or half of the diameter
S= stroke of crank

Pi x Diameter of Bore x Stroke x No. of Cylinders = CID(cubic inch displacement)

3.1416 4.000(2.000 x 2.000) 3.000 8 = 302
" " 3.125 8 = 314
" " 3.250 8 = 327
" " 3.400 8 = 342

3.1416 4.010(2.005 x 2.005) 3.000 8 = 303
" " 3.125 8 = 316
" " 3.250 8 = 328
" " 3.400 8 = 344

3.1416 4.020(2.010 x 2.010) 3.000 8 = 305
" " 3.125 8 = 317
" " 3.250 8 = 330
" " 3.400 8 = 345

3.1416 4.030(2.015 x 2.015) 3.000 8 = 306
" " 3.125 8 = 319
" " 3.250 8 = 331(actually 331.6)
" " 3.400 8 = 347

3.1416 4.040(2.020 x 2.020) 3.000 8 = 308
" " 3.125 8 = 320
" " 3.250 8 = 333
" " 3.400 8 = 349

btw, this forumla works for ALL engines, i just did this for 302(based) engines, since thats what came in the 5.0's......have fun.

btw, i dont know how to do import engine displacement, since they use mm's, instead of bore/stroke, but, im sure it wouldnt be hard, but, hey, we dont care about no STINKIN IMPORTS ON THIS SITE..........do we ??