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Old May 5, 2005 | 07:23 PM
  #11  
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mkspeed26
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Default RE: Bore&Stroke


ORIGINAL: NOS/408

i tell you its .. BORE X BORE X STROKE X 0.7854 X 8 = CU IN. O AND IM NEVER WRONG![&:] heres exp. 4.0 x 4.0 x 3.0 x 0.7854 x 8 =301.5936 just put your fuirges in my 408 is 4.030x4.030x4x0.7854x8=408.17928= 408 as for my big boy 4.530x4.530x4.5x0.7854x8=580.21612=580
ohhh, sh*t, i just creamed myslef. that is HUGE!!!! btw, i dont think she is lookin for the formula, she lookin for the concept.
Old May 5, 2005 | 07:38 PM
  #12  
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Default RE: Bore&Stroke

Everybody is on the same track just using different slants on the forumla.

Cyl. Volume = (R)2 * S * pi

The radius is half the Bore so:

Cyl. Volume = (B/2)2 * S * pi

expanding (B/2)2 by squaring both top and bottom gives you:

Cyl. Volume = (B)2 / (2)2 * S * pi

reducing pi/4 (.7853) gives you:

Cyl. Volume = (B)2 * S * .7853

That ends today's Geometry lesson.
Old May 5, 2005 | 07:45 PM
  #13  
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Magiarn71
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Default RE: Bore&Stroke

Yeah, she's getting way more info than she bargained for I bet!




Nos408, you can also do the formula with 3.14, if you use PI*r^2 * stroke * # of cyl

3.14 x (2.015 x 2.015) x 4 x 8 = 408.177

They just solved for R, radius, multiplied it times 2 to get the diameter and resolved to get the new factor. That way you use bore diameter not radius and its easier to figure out.
Old May 5, 2005 | 09:29 PM
  #14  
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Default RE: Bore&Stroke

isn't the cylinder a round shape so wouldn't we need to multiply by 3.14?
Old May 5, 2005 | 10:39 PM
  #15  
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Yes, you're right, but theres more than one way to write the equation. You multiply the radius squared by Pi to find the area of a circle. If you want to use the diameter instead, you have to use a different number. So if you had a circle with radius 2 (diameter 4):

2 x 2 x 3.14159 = 12.57

4 x 4 x .7854 = 12.57
Old May 5, 2005 | 10:43 PM
  #16  
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Default RE: Bore&Stroke

or it can be stated as this:

V = r2h X # cylinders

http://www.google.com/search?hl=en&l...linder+formula

stated
http://regentsprep.org/Regents/math/fsolid/Solids2.htm
and restated
http://www.education2000.com/demo/de...l/volcylin.htm
Old May 5, 2005 | 10:43 PM
  #17  
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oh right
Old May 5, 2005 | 10:44 PM
  #18  
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ORIGINAL: 5.0mustang5speed

i stroked my 302 to a 347...and used a longer rod
How can you possibly increase the displacement of your engine by using a longer connecting rod?? Unless you changed other things to get the increase?
Old May 5, 2005 | 11:05 PM
  #19  
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Default RE: Bore&Stroke


ORIGINAL: GreyStang


ORIGINAL: 5.0mustang5speed

i stroked my 302 to a 347...and used a longer rod
How can you possibly increase the displacement of your engine by using a longer connecting rod?? Unless you changed other things to get the increase?
well i dont think that is possible 302 to347 you can get a longer rod for more leverage at the crank...bore round stroke is long..??
Old May 5, 2005 | 11:05 PM
  #20  
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Magiarn71
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The only way to change stroke is to change the crank, no matter what size the rod is, the crank will move it up so far and down so far and thats it. If you had a rod a mile long and a 3 in stroke crank, it would still only move 3 inches.

But usually with a 347 you'd use a 5.4 rod instead of the 5.090, and a 3.4" not 3" crank.




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