Bore&Stroke
#11
RE: Bore&Stroke
ORIGINAL: NOS/408
i tell you its .. BORE X BORE X STROKE X 0.7854 X 8 = CU IN. O AND IM NEVER WRONG![&:] heres exp. 4.0 x 4.0 x 3.0 x 0.7854 x 8 =301.5936 just put your fuirges in my 408 is 4.030x4.030x4x0.7854x8=408.17928= 408 as for my big boy 4.530x4.530x4.5x0.7854x8=580.21612=580
i tell you its .. BORE X BORE X STROKE X 0.7854 X 8 = CU IN. O AND IM NEVER WRONG![&:] heres exp. 4.0 x 4.0 x 3.0 x 0.7854 x 8 =301.5936 just put your fuirges in my 408 is 4.030x4.030x4x0.7854x8=408.17928= 408 as for my big boy 4.530x4.530x4.5x0.7854x8=580.21612=580
#12
RE: Bore&Stroke
Everybody is on the same track just using different slants on the forumla.
Cyl. Volume = (R)2 * S * pi
The radius is half the Bore so:
Cyl. Volume = (B/2)2 * S * pi
expanding (B/2)2 by squaring both top and bottom gives you:
Cyl. Volume = (B)2 / (2)2 * S * pi
reducing pi/4 (.7853) gives you:
Cyl. Volume = (B)2 * S * .7853
That ends today's Geometry lesson.
Cyl. Volume = (R)2 * S * pi
The radius is half the Bore so:
Cyl. Volume = (B/2)2 * S * pi
expanding (B/2)2 by squaring both top and bottom gives you:
Cyl. Volume = (B)2 / (2)2 * S * pi
reducing pi/4 (.7853) gives you:
Cyl. Volume = (B)2 * S * .7853
That ends today's Geometry lesson.
#13
RE: Bore&Stroke
Yeah, she's getting way more info than she bargained for I bet!
Nos408, you can also do the formula with 3.14, if you use PI*r^2 * stroke * # of cyl
3.14 x (2.015 x 2.015) x 4 x 8 = 408.177
They just solved for R, radius, multiplied it times 2 to get the diameter and resolved to get the new factor. That way you use bore diameter not radius and its easier to figure out.
Nos408, you can also do the formula with 3.14, if you use PI*r^2 * stroke * # of cyl
3.14 x (2.015 x 2.015) x 4 x 8 = 408.177
They just solved for R, radius, multiplied it times 2 to get the diameter and resolved to get the new factor. That way you use bore diameter not radius and its easier to figure out.
#15
RE: Bore&Stroke
Yes, you're right, but theres more than one way to write the equation. You multiply the radius squared by Pi to find the area of a circle. If you want to use the diameter instead, you have to use a different number. So if you had a circle with radius 2 (diameter 4):
2 x 2 x 3.14159 = 12.57
4 x 4 x .7854 = 12.57
2 x 2 x 3.14159 = 12.57
4 x 4 x .7854 = 12.57
#16
RE: Bore&Stroke
or it can be stated as this:
V = r2h X # cylinders
http://www.google.com/search?hl=en&l...linder+formula
stated
http://regentsprep.org/Regents/math/fsolid/Solids2.htm
and restated
http://www.education2000.com/demo/de...l/volcylin.htm
V = r2h X # cylinders
http://www.google.com/search?hl=en&l...linder+formula
stated
http://regentsprep.org/Regents/math/fsolid/Solids2.htm
and restated
http://www.education2000.com/demo/de...l/volcylin.htm
#18
RE: Bore&Stroke
ORIGINAL: 5.0mustang5speed
i stroked my 302 to a 347...and used a longer rod
i stroked my 302 to a 347...and used a longer rod
#19
RE: Bore&Stroke
ORIGINAL: GreyStang
How can you possibly increase the displacement of your engine by using a longer connecting rod?? Unless you changed other things to get the increase?
ORIGINAL: 5.0mustang5speed
i stroked my 302 to a 347...and used a longer rod
i stroked my 302 to a 347...and used a longer rod
#20
RE: Bore&Stroke
The only way to change stroke is to change the crank, no matter what size the rod is, the crank will move it up so far and down so far and thats it. If you had a rod a mile long and a 3 in stroke crank, it would still only move 3 inches.
But usually with a 347 you'd use a 5.4 rod instead of the 5.090, and a 3.4" not 3" crank.
But usually with a 347 you'd use a 5.4 rod instead of the 5.090, and a 3.4" not 3" crank.