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Displacement and...math (Sorry)

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Old 03-23-2013, 12:37 PM
  #11  
JFitz
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Well, I knew they were measuring displacement by the volume of each cylinder from TDC to BDC x the number of cylinders.

Just didn't know the rest.


Good to know.
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Old 03-26-2013, 07:33 PM
  #12  
JIM5.0
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jpplaw's method is probably the easiest method to calculate geometric displacement.

The way I memorized it is using classic middle school volumes calculation:
1 cylinder volume = pi*h*r^2
or 3.1416(stroke)(bore/2)(bore/2) where
Pi = 3.1416
h = full stroke from BDC to TDC
r = bore/2

Once you calculate the volume of one cylinder, you are right: just multiply by 8 for 8 cylinders.

The Coyote engine has the following dimensions for displacement:
Bore = 92.2 mm or 3.63 inch
Stroke = 92.8 mm or 3.65 inch

Using either jpplaw's equation or mine, the same numbers come up:

jpplaw's method: 3.630" x 3.630" x 3.650" x 8 x .78545 = 302.214 ci (Note the rounding error, but very very close)

My method: 3.1416 (3.630"/2) (3.630"/2) (3.650") (8) = 302.195 ci (Again, rounding error, but very close)

Now metric: 3.1416 (92.2mm/2) (92.2mm/2) (92.8mm) (8) = 4,956,677.9 cubic mm
We need to convert to Liters, divide by 1 million. There are 1 million cubic mm in one Liter.
4,956,677.9 cubic mm = 4.957 L, which by industry standard is rounded up to 5.0L.
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Old 03-26-2013, 08:13 PM
  #13  
Nuke
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Thanks, guyz. This thread is better than a glass of warm milk with a shot of brandy. G'nite...
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Old 03-30-2013, 09:55 AM
  #14  
157dB
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Is that dynamic compression or static compression.

*****

just for you nuke
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