410s in a automatic ?
3rd Gear Member
Joined: Nov 2005
Posts: 701
From:
RE: 410s in a automatic ?
ORIGINAL: Mpaint99
3k at 80 MPH with Im hoping you meant 18 tires in back makes my decision easier. I also have 18's .Thanks also for the Richmond gear website. I dont know the overdrive ratio ?
3k at 80 MPH with Im hoping you meant 18 tires in back makes my decision easier. I also have 18's .Thanks also for the Richmond gear website. I dont know the overdrive ratio ?
5th Gear Member
Joined: Mar 2006
Posts: 2,179
From: Nor Cal
RE: 410s in a automatic ?
ORIGINAL: Mpaint99
3k at 80 MPH with Im hoping you meant 18 tires in back makes my decision easier. I also have 18's .Thanks also for the Richmond gear website. I dont know the overdrive ratio ?
3k at 80 MPH with Im hoping you meant 18 tires in back makes my decision easier. I also have 18's .Thanks also for the Richmond gear website. I dont know the overdrive ratio ?
Richard
Joined: Dec 2006
Posts: 44
From:
RE: 410s in a automatic ?
MPaint, thanks
By the way, you can calculate your tire size (diameter) as follows. If I remember right a stock tire is roughly 27.5 inches in diameter. If you have after market wheels and tires you can use the following example to caculate your tire diameter.
If your tire is a 275/35/20 you can calculate the diameter by taking 275/25.4 (conversion from millmeters to inches) this gives you 10.83 inches, you than multiply that by 35% or actually .35 (the 35 in your tire size number or whatever it is in yours) this gives you 3.79 inches in this example. That gives you the height of your sidewall. Since your tire effectively has an upper and lower sidewall you need to double that number which is equal to 7.58 inches. Finally you add the size of the rim to the eqaution in this case it is 20 inches and bingo you have your tire diameter of 27.58 inches.
My understanding is that you can than take that as a ratio to determine what your effective gearing would be. In this case it would be (27.5/27.58)x4.10 which will give you an effective gear ratio of 4.04.
By the way, you can calculate your tire size (diameter) as follows. If I remember right a stock tire is roughly 27.5 inches in diameter. If you have after market wheels and tires you can use the following example to caculate your tire diameter.
If your tire is a 275/35/20 you can calculate the diameter by taking 275/25.4 (conversion from millmeters to inches) this gives you 10.83 inches, you than multiply that by 35% or actually .35 (the 35 in your tire size number or whatever it is in yours) this gives you 3.79 inches in this example. That gives you the height of your sidewall. Since your tire effectively has an upper and lower sidewall you need to double that number which is equal to 7.58 inches. Finally you add the size of the rim to the eqaution in this case it is 20 inches and bingo you have your tire diameter of 27.58 inches.
My understanding is that you can than take that as a ratio to determine what your effective gearing would be. In this case it would be (27.5/27.58)x4.10 which will give you an effective gear ratio of 4.04.
2nd Gear Member
Joined: Jan 2005
Posts: 482
From:
RE: 410s in a automatic ?
Yes, as jbailer & 06GT4RAD explained, my rear tires are (a little over) 28" tall, 295/45/18s. Stock tires are closer to 27". With the taller tires you are spinning a little less on the motor.
27/28.25=95.6%, 3,000/95.6%=3,138
If I were on the stock tires I would only spin at 3,138rpm where I now spin 3k.
27/28.25=95.6%, 3,000/95.6%=3,138
If I were on the stock tires I would only spin at 3,138rpm where I now spin 3k.
2nd Gear Member
Joined: Jan 2005
Posts: 482
From:
RE: 410s in a automatic ?
ORIGINAL: Captaincobalt
MPaint is that through measurement or by caclulating it? Measurement is not as exact.
MPaint is that through measurement or by caclulating it? Measurement is not as exact.